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smokebomb13 smokebomb13
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Posts: 125
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11 years ago
Your Open QuestionShow me another »
Precalculus summer homework help...?
i need some help with these problems. can you please tell me how to do these thanks.
1. the lines L1 and L2 are perpendicular and given by
L1: 4ax+2by=1 L2: 3ax-by=5
find 12(a^2)+4b^2
2.for real numbers m and n, let m(+)n=2mn-n^3. find 4(+)2. (the + sign is inside a circle)

3.for what values of k does the equation (x^2)-kx+1=0 have imaginary roots?

4.let f(x)=x^3-ax^2+bx-c. if f(0)=1 and f(1)=4. find b-a

5.which of the following functions are one-to-one?
a) y=lxl
b)y=4x-3
c)y=(3x+4)/ (x-2)
6.find the equation of the perpendicular bisector of the segment joining P(-2,-4) and Q(8,-8)

7. write a polynomial equation that has the following three roots:
5, (5i(? 3)-5)/2, and (-5i? 3-5)/2
i really want to know HOW to do these. thanks
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iluvtalkingiluvtalking
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11 years ago
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wrote...
11 years ago
2by = -4ax + 1
y = (-2a/b)x + 1/(2b)

by = 3ax - 5
y = (3a/b)x + 5/b

-2a/b = -b/(3a)
-6a^2 = -b^2
6a^2 = b^2
?(6)a = b

12a^2 + 24a^2
36a^2
No idea what a equals.

----------------

2(4)(2) - (2)^3
16 - 8
8

----------------

x^2 - kx + 1 = 0
k ? 2

------------------

c = -1
-a + b = 3

---------------

a) no
b) yes
c) i think so

------------------

(x - 5)(2x + 5)^2 = (5i?(3))(-5i?(3))
(x - 5)(2x + 5)^2 = 25*3
(x - 5)(2x + 5)^2 = 75
(x - 5)(4x^2 + 20x + 25) = 75
4x^3 - 20x^2 + 20x^2 - 100x + 25x - 125 = 75
4x^3 - 75x - 200 = 0
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