Bug in software

Alpha decay emits an alpha particle (A Helium atom):
[math=inline]{}^4_2mathrm{He}

{}^{14}_6mathrm{C} -> {}^{10}_4mathrm{Be} + {}^4_2mathrm{He}[/math]
notice that 14 = 4 + 10 and 6 = 2 + 4 (the sides are balanced)
The resultant species is Beryllium-10 because the atomic number is 4.  The mass number is 10, but this only identifies which isotope of Be is present, not the identity of the element.

β[sup]-[/sup] decay emits an electron and an antineutrino (to conserve energy):
[math=inline]{}^{14}_6mathrm{C} -> {}^{14}_7mathrm{N} + {}^0_{-1}mathrm{{e^{-}}}[/math] + [sup]¯[/sup]v[sub]e[/sub]
In this case, the substance decays to Nitrogen-14 (atomic number 7)

β[sup]+[/sup] decay emits a positron and a neutrino (to conserve energy):
[math=inline]{}^{14}_6mathrm{C} -> {}^{14}_5mathrm{B} + {}^0_{1}mathrm{{e^{+}}} + {{v}_{e}}[/math]
In this case, the substance decays to Boron-14 (atomic number 5)

[u]Uranium-248[/u] ([math=inline]{}^{248}_{92}mathrm{U}[/math]):
[math=inline]{alpha}-decay:{}^{248}_{92}mathrm{U} -> {}^{244}_{90}mathrm{Th} + {}^4_2mathrm{He}

{{eta}^{-}} decay: {}^{248}_{92}mathrm{U} -> {}^{248}_{93}mathrm{Np} + {}^0_{-1}mathrm{{e^{-}}} + {^{-}}{{v}_{e}}

{{eta}^{+}} decay: {}^{248}_{92}mathrm{U} -> {}^{248}_{91}mathrm{Pa} + {}^0_{1}mathrm{{e^{+}}} + {{v}_{e}}[/math]


[u]Potassium-40[/u] ([math=inline]{}^{40}_{19}mathrm{K}[/math]):
[math=inline]{alpha}-decay: {}^{40}_{19}mathrm{K} -> {}^{36}_{17}mathrm{Cl} + {}^4_2mathrm{He}

{{eta}^{-}} decay: {}^{40}_{19}mathrm{K} -> {}^{40}_{20}mathrm{Ca} + {}^0_{-1}mathrm{{e^{-}}} + {^{-}}{{v}_{e}}

{{eta}^{+}} decay: {}^{40}_{19}mathrm{K} -> {}^{40}_{18}mathrm{Ar} + {}^0_{1}mathrm{{e^{+}}} + {{v}_{e}}[/math]
[fieldsettop]Post Merge: [time]29-10-2013, 00:00[/time][/fieldsettop]
Just an aside, when someone refers to beta-decay and doesn't specify +/-, it's assumed they're talking about β[sup]-[/sup] decay (emission of an electron and an antineutrino).