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shannonmcqu shannonmcqu
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Posts: 7
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10 years ago
A plant grown from a [round, yellow] seed is crossed with a plant grown from a [wrinkled, yellow] seed. This cross produces four progeny types in the F1:

[round, yellow], [wrinkled, yellow], [round, green], and [wrinkled, green].

Use this information to deduce the genotypes of the parent plants.

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wrote...
Staff Member
Educator
10 years ago
Try RRYy and rrYy
magiter12,  ROD18
Mastering in Nutritional Biology
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Answer accepted by topic starter
shannonmcqu Authorshannonmcqu
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Posts: 7
Rep: 6 0
10 years ago
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wrote...
Staff Member
Educator
10 years ago
NP
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
10 years ago
The answer was RrYy and rrYy

thank you though! Slight Smile

I can confirm that this is the answer, thank you kindly!
krad7890
wrote...
Staff Member
Educator
10 years ago
NP
beyou
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
10 years ago
The correct answer is RrYy and rrYy
wrote...
10 years ago
thank you
wrote...
10 years ago
thank you!!
wrote...
10 years ago
Thanks
wrote...
10 years ago
Got the same thing!
wrote...
10 years ago

    First, eliminate those genotypes that are inconsistent with the phenotypes of the parents.

    Then examine the remaining possibilities: Which are consistent with the phenotypes of the progeny?

Because the cross produces green progeny (and both parents are yellow), both parents must be Yy: If either parent were YY, only yellow progeny would result.

The cross also produces wrinkled progeny, so the [round, yellow] parent must be heterozygous (Rr): If it were RR, all of the progeny would be Rr and have a round phenotype.
wrote...
10 years ago
This helped a lot thank you
wrote...
10 years ago
The answer is RrYy and rrYy
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