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JaeYang JaeYang
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Posts: 17
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9 years ago
Assume that during meiosis I, none of the C chromosomes disjoin at metaphase, but they separate into dyads (instead of monads) during meiosis II. Each resultant gamete participated in fertilization with a normal haploid gamete. What combinations will result?


Check all that apply.
   A) two copies of chromosome A, two copies of chromosome B, four copies of chromosome C
   B) two copies of chromosome A, one copy of chromosome B, three copies of chromosome C
   C) two copies of chromosome A, two copies of chromosome B, five copies of chromosome C
   D) two copies of chromosome A, two copies of chromosome B, one copy of chromosome C
   E) two copies of chromosome A, two copies of chromosome B
   F) two copies of chromosome A, two copies of chromosome B, two copies of chromosome C
   G) two copies of chromosome A, two copies of chromosome B, three copies of chromosome C
   H) one copy of chromosome A, two copies of chromosome B, three copies of chromosome C
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