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Solutions | Approved: 7 years ago | 447 kB | Comments: 0
Category: Chemistry | Downloaded: 0
...KI (Hsoln =+21.5 kJ/mol) and MgCl2 (Hsoln...
...(Hsoln = –150 kJ/mol)? Use Table 13.1...
...KI is –336 kJ/mol (K+) + –247...
...(K+) + –247 kJ/mol (I–) = –583kJ/mol....
...MgCl2 is –1903 kJ/mol (Mg2+) + 2(–313...
...(Mg2+) + 2(–313 kJ/mol) (Cl–) = –2529kJ/mol...
...+ Hhydration +21.5 kJ/mol = –U +...
...–U + –583 kJ/mol 604.5 kJ/mol =...
...–583 kJ/mol 604.5 kJ/mol = –U 604...
...= –U 604 kJ/mol = U =...
...+ Hhydration –150 kJ/mol = –U +...
...–U + –2529 kJ/mol 2379 kJ/mol =...
...–2529 kJ/mol 2379 kJ/mol = –U –2379...
...= –U –2379 kJ/mol = U Example...
...J  =  +59.2 kJ/mol Example 3 What...
...J/mol or 41.0 kJ/mol Using the equation...
...4 x 10–2 kJ/mol >> Example 3...
...CH2ClCH2Cl       G° = –148 kJ/mol at 500 K...
...Cl–       G° = +28.1 kJ/mol at 25 °C...
...H° of +77.2 kJ/mol, what is the...
...kJ by 77.2 kJ/mol x (1000 J/1...
N/A 380
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