...already known (1.01 mol HCl). We need...
...weight) = 2(22.99 g/mol) + 32.07 g/mol...
...g/mol) + 32.07 g/mol + 4(16.00 g/mol)...
...g/mol + 4(16.00 g/mol) = 142.05 g...
...= 142.05 g Na2SO4./mol Na2SO4. Find the...
...Na2SO4 = 0.106 mol Na2SO4 Find the...
...Na2SO4 = 0.106 mol Na2SO40.3930 L solution...
...Na2SO4 = 0.106 mol Na2SO40.4000 kg water...
...simplest route: 0.270 mol Na2SO4L solution x...
...solution x 2 mol Na+1 mol Na2SO4...
...2 mol Na+1 mol Na2SO4 x 22.99...
...22.99 g Na+1 mol Na+ x 1000...
...fraction SO42- = mol SO42-mol SO42- +...
...SO42- = mol SO42-mol SO42- + mol...
...SO42-mol SO42- + mol Na+ + mol...
...mol Na+ + mol H2O Find the...
...Na2SO4 x 2 mol Na+1 mol Na2SO4...
...2 mol Na+1 mol Na2SO4 = 0.212...
...Na2SO4 = 0.212 mol Na+ Find the...
...SO42- : 0.106 mol Na2SO4 x 1...
...Na2SO4 x 1 mol SO42-1 mol Na2SO4...
...1 mol SO42-1 mol Na2SO4 = 0.106...
...Na2SO4 = 0.106 mol SO42- Find the...
...H2O x 1 mol H2O18.02 g H2O...
...H2O = 22.20 mol H2O Calculate the...
...SO42- = 0.106 mol SO42-0.212 mol Na+...
...0.106 mol SO42-0.212 mol Na+ + 0.106...
...Na+ + 0.106 mol SO42- + 22.20...
...SO42- + 22.20 mol H2O = 0.00471...
...you have 12.0 mol HCl present. Convert...
...of HCl: 12.0 mol HCl x 36.46...
...36.46 g HCl1 mol HCl = 437.5...
...the molality: 12.0 mol HCl0.670 kg H2O...
...H2O x 1 mol H2O18.02 g H2O...
...H2O = 37.2 mol H2O Calculate the...
...HCl = 12.0 mol HCl12.0 mol HCl...
...12.0 mol HCl12.0 mol HCl + 37.2...
...HCl + 37.2 mol H2O = 0.244...
...you have 0.300 mol Ca(NO3)2. To find...
...weight) = 40.08 g/mol + 2(14.01 g/mol)...
...g/mol + 2(14.01 g/mol) + 6(16.00 g/mol)...
...g/mol) + 6(16.00 g/mol) = 164.10 g...
...= 164.10 g Ca(NO3)2/mol Ca(NO3)2 Calculate the...
...Ca(NO3)2 : 0.300 mol Ca(NO3)2 x 164.10...
...164.10 g Ca(NO3)21 mol Ca(NO3)2 = 49.2...
...weight) = 14.01 g/mol + 3(16.00 g/mol)...
...g/mol + 3(16.00 g/mol) = 62.01 g...
...= 62.01 g NO3¯/mol NO3¯ Calculate the...
...nitrate ion: 0.300 mol Ca(NO3)2 x 2...
...Ca(NO3)2 x 2 mol NO3-1 mol Ca(NO3)2...
...2 mol NO3-1 mol Ca(NO3)2 x 62.01...
...62.01 g NO3-1 mol NO3- = 37.2...
...calcium ion: 0.300 mol Ca(NO3)2 x 1...
...Ca(NO3)2 x 1 mol Ca2+1 mol Ca(NO3)2...
...1 mol Ca2+1 mol Ca(NO3)2 x 40.08...
...40.08 g Ca2+1 mol Ca2+ = 12.0...
...the molarity: 0.300 mol Ca(NO3)21.040 L solution...
...nitrate ions: 0.288 mol Ca(NO3)21 L solution...
...solution x 2 mol NO3-1 mol Ca(NO3)2...
...2 mol NO3-1 mol Ca(NO3)2 = 0.576...
...calcium ion: 0.300 mol Ca(NO3)2 x 1...
...Ca(NO3)2 x 1 mol Ca2+1 mol Ca(NO3)2...
...1 mol Ca2+1 mol Ca(NO3)2 = 0.300...
...Ca(NO3)2 = 0.300 mol Ca2+ Find the...
...nitrate ion: 0.300 mol Ca(NO3)2 x 2...
...Ca(NO3)2 x 2 mol NO3-1 mol Ca(NO3)2...
...2 mol NO3-1 mol Ca(NO3)2 = 0.600...
...Ca(NO3)2 = 0.600 mol NO3- Find the...
...H2O x 1 mol H2O18.02 g H2O...
...H2O = 55.49 mol H2O Calculate the...
...calcium ion: 0.300 mol Ca2+0.300 mol Ca2+...
...0.300 mol Ca2+0.300 mol Ca2+ + 0.600...
...Ca2+ + 0.600 mol NO3- + 55.49...
...NO3- + 55.49 mol H2O = 0.00532...
...nitrate ion: 0.600 mol NO3-0.300 mol Ca2+...
...0.600 mol NO3-0.300 mol Ca2+ + 0.600...
...Ca2+ + 0.600 mol NO3- + 55.49...
...NO3- + 55.49 mol H2O = 0.0106...
...Mg2+ x 1 mol Mg2+24.30 g Mg2+...
...Mg2+ x 2 mol Cl-1 mol Mg2+...
...2 mol Cl-1 mol Mg2+ x 35.45...
...35.45 g Cl-1 mol Cl- = 0.0729...
...Mg2+ x 1 mol Mg2+24.30 g Mg2+...
...g Mg2+ x1 mol MgCl21 mol Mg2+...
...x1 mol MgCl21 mol Mg2+ x 95.20...
...95.20 g MgCl21 mol MgCl2 = 0.0979...
...MgCl2 x 1 mol MgCl295.20 g MgCl2...
...MgCl2 = 0.00103 mol MgCl2 Calculate the...
...of MgCl2: 0.00103 mol MgCl21 L solution...
...magnesium ions: 0.00103 mol MgCl21 L solution...
...solution x 1 mol Mg2+1 mol MgCl2...
...1 mol Mg2+1 mol MgCl2 = 0.00103...
...x 2mol Cl-1 mol MgCl2 = 0.00206...
...MgCl2 = 0.00206 mol Cl- 4 g....
...of MgCl2: 0.00103 mol MgCl20.9999021 kg H2O...

...contained in 0.644 mol oxygen? a. 10.3...
...6.51 ? 10?2 mol b. 3.68 ?...
...3.68 ? 10?1 mol c. 4.09 ?...
...4.09 ? 10?2 mol d. 1.21 ?...
...1.21 ? 10?1 mol e. 1.17 ?...
...1.17 ? 10?3 mol ANS: A OBJ:...
...g d. 16 mol e. 4 mol...
...mol e. 4 mol ANS: C DIF:...
...weight of 92.0 g/mol. What is its...
...to be 32 g/mol. What is its...
...be approximately 88 g/mol. What is its...
...mass of 88 g/mol. If butyric acid...
...atoms? a. 0.407 mol b. 2.46 mol...
...mol b. 2.46 mol c. 3.57 mol...
...mol c. 3.57 mol d. 16.3 mol...
...mol d. 16.3 mol e. 98.5 mol...
...mol e. 98.5 mol ANS: B OBJ:...