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Home Q & A Board Science-Related Homework Help Physics
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12 years ago
A force of 4.0 N applied to a spring compresses it by 8.0 cm. What is the amount of work done to compress the spring by an additional amount of  5.0 cm?
A) 20 J
B) 0.26 J
C) 0.50 J
D) 2.0 J
E) 50 N/m
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wrote...
#1
12 years ago
The answer is b)

F = - kx => 4N = -k(-0.08m) => k=50N/m

the work done to compress a spring an additional 5 cm is the difference between the work needed to compress the spring by 13 cm and the work done in compressing it by 8 cm

W=1/2 kx^2

so the work done in compressing it the final 5 cm is:

1/2(50)(0.13)^2 - 1/2(50)(0.08)^2=0.26J
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