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Whelan Whelan
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Posts: 3158
9 years ago
The balanced equation for the solubility equilibrium of Ba(OH)2 is shown below. What is the equilibrium constant expression for the Ksp of Ba(OH)2?

Ba(OH)2(s) Leftwards Arrow Rightwards Arrow Ba2+(aq) + 2 OH-(aq)

A) Ksp = {[Ba2+][OH-]2}/{[Ba(OH)2][H2O]}
B) Ksp = {[Ba2+][OH-]2}/[Ba(OH)2]
C) Ksp = [Ba2+][OH-]2
D) Ksp = 1/{[Ba2+][OH-]2}
Textbook 
Introductory Chemistry Essentials

Introductory Chemistry Essentials


Edition: 5th
Author:
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hbutler2hbutler2
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9 years ago
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Whelan Author
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9 years ago
Thanks
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Yesterday
I appreciate what you did here, answered it right Smiling Face with Open Mouth
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2 hours ago
Thanks
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