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rkim12 rkim12
wrote...
Posts: 105
Rep: 1 0
11 years ago
A color blind man with blood type AB, whose mother has normal vision, marries a woman with blood type O and normal vision, whose mother was color blind. If they have 16 children, how many boys will be both color blind and blood type A? Write genotype of the married couple. Show a Punnet Square
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wrote...
11 years ago
Blood type:  
Man   IA IB x i i   Woman =>
1/2 type IA
1/2 type IB
(both get an i from mom, so only dad's allele determines blood type)

Color blindness is X-linked Recessive, and mom must be heterozygous bc grandma was colorblind:

  Mom  Xb XB  x   Xb Y  Dad =>
1/4 Xb Xb (colorblind daughter)
1/4 XB Xb (daughter with normal vision)
1/4 Xb Y   (Colorblind son)
1/4 XB Y - (son with normal vision)

I would set it up as two separate Punnet Squares, the multiply the individual probabilities:

 16 children x 1/4 colorblind son x 1/2 blood type A
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