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smithla03 smithla03
wrote...
Posts: 28
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11 years ago
Using the properties of determinants, how do I show that the determinants of the following matrices are equal?:

x 0 1 1
0 x 1 1
1 1 x 0
1 1 0 x

-x 0 1 1
0 -x 1 1
1 1 -x 0
1 1 0 -x
Thank you!
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wrote...
11 years ago
to the 2nd determinant do the following operations and automatically the answer will come out


r1-> - r1
c4-> - c4
r2-> - r2
c3-> - c3

since it done 4 times all the negatives will get cancelled out

sorry i was in a bit of hurry cudnt write the determinant in every step

hope it helps
wrote...
11 years ago

The theory underlying determinant is this:  There are 3 elementary row operations: 1. row interchange; 2. multiply a row by a constant; and 3. replace a row with combination of the other rows.

The determinant of row operation #2 (multiply a row by a constant r) is = to multiplying the determinant by r.

Since the second matrix involves multiplying 4 rows by -1, then four elementary row operations (#2) are performed.  The resulting determinant = (-1)^4 = 1.  So the determinant of the second matrix = (-1)^4 * determinant of the first.
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