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Leon95 Leon95
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11 years ago
A constant force of 21 N pulls on a 13 Kg block on a horizontal surface. The force is directed at 28o above the horizontal. A friction force impedes the motion. What is the work done by the constant force when the block is moved 9 meters?
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Leo
wrote...
11 years ago
The component of 21 N force that acts in direction of motion = 21 cos 28 = 18.5 N
The work done by this component = work done by 21 N force = (18.5)(9) = 167 J ANS
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