× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
6
w
4
c
4
r
4
m
3
m
3
u
3
m
3
e
3
k
3
N
3
y
3
New Topic  
justinrocks justinrocks
wrote...
Posts: 4
Rep: 0 0
11 years ago
How do I find a Cartesian equation for the polar curves:

A) r = 2csc?

B) r = 2tan?sec?

If someone could show step by step how to solve this problem it would be helpful.
Read 449 times
1 Reply

Related Topics

Replies
wrote...
11 years ago
A) y = r*sin(t)
y = 2csc(t)*sin(t) = 2
y = [2/sin(t)]*sin(t)
y = 2

B) r = 2tan(t)*1/cos(t)
x =  2tan(t)*1/cos(t)*cos(t) = 2tan(t)
tan(t) = x/2
y =  2tan(t)*1/cos(t)*sin(t) = 2tan^2(t)
y = 2*x^/4 = x^2/2
y = (1/2)*x^2
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  525 People Browsing
Related Images
  
 228
  
 332
  
 405
Your Opinion
Where do you get your textbooks?
Votes: 447

Previous poll results: What's your favorite math subject?