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Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
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FIREMEDIC73 FIREMEDIC73
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11 years ago
Assuming that the gene for black body is autosomal.
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#1
11 years ago
Let's call the allele B=black and B+ = wild type

The formula we use is B^2 + 2B(B+) + (B+)^2 = 1, where B^2 is the frequency of the black homozygotes, 2B(B+) is the frequency of heterozygotes and (B+)^2 is the frequency of wild type homozygotes. We need to convert the numbers to a percentage, so add them all together and divide.
B^2 = 64/(64+621)*100 = 9
Hence B = sqr root 9 = 3. That means the frequency is 0.3
The two alleles must add to a frequency of 1, so 1- 0.3 = 0.7.
B+= 0.7, B = 0.3
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