How can i make a buffer solution by?

The Henderson-Hasselbalch equation can be used-
pH = pKa + log(A-/HA) where (in this case) A- is the concentration of the sodium acetate, HA is the concentration of acetic acid, and pKa is the negative log of the acid dissociation constant of acetic acid..
The Ka for acetic acid is 1.76x10^-5, so the pKa = -log(1.76x10^-5) = 4.75
You wanted HA (acetic acid) to be 1.00 M and the pH to be 4.82.
4.82 = 4.75 + log(A-/1.00)
log(A-/1.00) = 0.07
A- = 1.175 M
For 50 mL (0.050 L) you need 0.050 mole acetic acid and 0.0588 mole sodium acetate.
You need 60.05 x 0.050 grams of acetic acid (3.00 g) and 0.0588 x 82.04 grams od sodium acetate (4.82 g) dissolved in enough water to make 50.00 mL of buffer solution.