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Sektor404 Sektor404
wrote...
Posts: 125
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11 years ago
1) From the following 4 metals, which combination would you use to make a cell that would generate the largest potential difference? Zn, Cu, Fe and Ni.

2) From the combination deduced from above, which would be connected to the anode and which would be connected to the cathode? (labelling the electrode connected to the positive terminal of the voltmeter as the right-hand electrode).

3) Write the half-equations for the cell.

4) Does the anode and cathode change if the electrode connected to the positive terminal of the voltmeter is changed?

5) Does the cell reaction change?
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wrote...
Subject Expert
11 years ago
Hi Sektor404,

1) I would use Cu and Zn.

2) Whichever on the cathode will get reduced and whichever on the anode will get oxidized.
So Cu2+(aq) and Cu(s) would be on the cathode, where Cu2+ would be reduced to Cu(s)
And Zn2+(aq) and Zn(s) would be on the anode, where Zn(s) would be oxidized to Zn2+(aq)

3) Reduction:  Cu2+(aq) + 2e-  ---> Cu(s)
    Oxidation:   Zn(s)                ---> Zn2+(aq) +2e-

4) No, it would not change, but the voltage reading would become negative instead of positive.

5) No

Hope this helps,
Laser
Sektor404 Author
wrote...
11 years ago
Hi Laser_3,

Thank you so much for your help Slight Smile Greatly appreciated!
wrote...
Staff Member
11 years ago
Marking this solved, thanks Laser.
- Master of Science in Biology
- Bachelor of Science
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