Question 16
Numerical Response
Choose the correct genotype number for each description of an offspring. Genotype number: ____________ ____________ ____________ ____________
Offspring Description: Homozygous Genotype similar to Heterozygous Recessive
genotype one of the parents genotype phenotype
THUMBNAIL #1
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Question 17Gray eyes are inherited as a recessive trait.
Two brown-eyed individuals had a gray-eyed offspring.
Which of the above crosses would result from the genotype of the parents? A) A.
B) B.
C) C.
D) D.
HINT: Logic words? Two
brown-eyed parents!
THUMBNAIL #2
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Question 18In mice with complete dominance in coat colour, brown (B) is dominant to white (b). The genotypes BB, Bb, and bb represent:A) two genotypes
B) two phenotypes
C) three phenotypes
D) one phenotype
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Question 19Mendel's Law of Segregation separates alleles in forming gametes. Beginning with the genotype (Ww), how would these genes be distributed among four sperm cells?A) all
W or all
wB) many ways as a matter of chance
C)
WW, Ww, Ww, wwD) two containing
w and two containing
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Question 24
Tall pea plants are dominant to dwarf pea plants. If no dwarf plants appeared after five generations of tall plants crossed with short plants, one can hypothesize that the tall plants:A) were dominant
B) were homozygous
C) had the gene for dwarfness on the same chromosome
D) were heterozygous
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Question 25If incomplete dominance exists between red and white snapdragons, then the correct genotype of a pink flower and the phenotype of a red flowered-parent, respectively, is:A) RW:RR
B) RW:parent → red
C) pink:RR
D) WW:RR
HINT: After reading (sr) gen 2, did you change the format in how you assigned symbols?
(a)
BB (b)
green (c)
YY (d)
YB or
BY(e)
No, the individual would be
green (BY)If you wrote the
Y first in
YB you would continue to do so all through the Punnett square.
BY would be equally correct, but then the
B would be written first for all green
BY's in the question.
THUMBNAIL #3
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Question 26If there is a lack of dominance among black and white horses, then the percentage that will be black if a white horse is mated with a gray horse is:A) 0%
B) 75%
C) 50%
D) 25%
HINT: Note that in codominance or incomplete dominance, it is not necessary to use homozygous for black or white. Since black can only be BB, a heterozygous BW would have the phenotype gray.
THUMBNAIL #4
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Question 27In a case of incomplete dominance, pink flowers are produced from the mating of pure four-o'clock plants.
Numerical Response
Choose the correct allele combination number from the legend for each of the folowing. Number : ___________ ___________ ___________
genotype 4 allele 2 genotype 3
THUMBNAIL #5
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Question 28
In a case of incomplete dominance, pink flowers are produced from the mating of pure four-o'clock plants.
Numerical Response
If a first filial cross mates genotype 3 x genotype 2, then the phenotypic ratio is: Answer: ______ : ______ : ______
white pink red
THUMBNAIL #5
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Question 29A pea plant that is heterozgous tall and having homozygous green pods has the genotype and phenotype, respectively, of: A) TTGG: height → dwarf; pod colour → green
B) TTGg: height → tall; pod colour → yellow
C) ttgg: height dwarf; pod colour → yellow
(This is a true description of ttgg, but does it answer the question?)
D) TtGG: height → tall; pod colour → green
HINT:
If the questions represent an individual parent, each genotype should have two alleles for the first trait, and two alleles for the second trait (4 letters in total).
(a)
TTGG; if the symbol
T for tallness is written first, then continue with
T or t's first all throughout the question.
(b)
TtGg; both traits exhibit the heterozygous condition
(c)
ttgg; even if described as yellow dwarf, it is written ttgg as the tall trait has been indicated to be written first.
(d)
TTGG; even though green is described first,
TTGG(e)
Ttyy(f)
ttGg; are you getting better at forming the genotype in dihybrid inheritance?
(g)
ttgg (homozygous recessive); used to test if the other parent is homozygous or heterozygous for a trait.
THUMBNAIL #6
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Question 30The genotype of a parent generation in which a yellow heterozygous tall pea plant is pollinated with a dwarf heterozygous green plant is: A) P1 = Ttgg x ttGg
B) P1 = Ttgg x ttgg
C) P1 = Ttgg x ttGG
D) P1 = TtGg x TtGg
HINT:
(a)
TtGg x
ttgg(b)
TtGg x
TtGg (actually, any combination)
(c)
ttGG x
TTggIf you start writting the tall trait first, continue this pattern all throughout the question.
THUMBNAIL #7