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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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biostudent123 biostudent123
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10 years ago Edited: 10 years ago, biostudent123
Question: The oxidation of 2-butanone (CH3COC2H5) by the cerium(IV) ion in aqueous solution to form acetic acid (CH3CO2H) occurs according to the following balanced equation:
CH3COC2H5(aq)+6Ce4+(aq)+3H2O(l)→ 2CH3CO2H(aq)+6Ce3+(aq)+6H+(aq)

A) If acetic acid appears at an average rate of 5.2×10−8M/s what is Δ[H+]Δt during the same time interval?

B) What is the average rate of consumption of Ce4+ during the same time interval?

I got A) wrong i multpled 5.2x 10-8M/s with 1/2, ...since Acetic acid has 2 moles in product

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AlexxAlexx
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10 years ago
Quote from: biostudent123 (10 years ago)
Question: The oxidation of 2-butanone (CH3COC2H5) by the cerium(IV) ion in aqueous solution to form acetic acid (CH3CO2H) occurs according to the following balanced equation:
CH3COC2H5(aq)+6Ce4+(aq)+3H2O(l)→ 2CH3CO2H(aq)+6Ce3+(aq)+6H+(aq)

A) If acetic acid appears at an average rate of 5.2×10−8M/s what is Δ[H+]Δt during the same time interval?

B) What is the average rate of consumption of Ce4+ during the same time interval?

I got A) wrong i multpled 5.2x 10-8M/s with 1/2, ...since Acetic acid has 2 moles in product



you're forgetting to take into consideration the 6 moles of hydrogen that forms per 2 moles of acetic acid formed.....if the rate of formation for acetic acid is 5.2*10 ^ -8 M/s ....then the formation of hydrogen should be 6/2 = 3 times that value.... so simplified should be (5.2*10 ^ - 8 M/s) *3 ...from the looks of it, B should be the same answer as A since it's another 6/2 ratio ..I haven't taken gen chem in awhile, so someone might need to verify, but I'm pretty sure my reasoning is correct.....

haha alexx you got me this time
biostudent123 Author
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#3
10 years ago
Thank you so much, Neji and Alex, i didnt take into account the H+.
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