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Home Q & A Board Science-Related Homework Help Physics
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ouch6767 ouch6767
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10 years ago
A proton moving with a velocity of 4.0×104 m/s along the +y-axis enters a magnetic field of 0.20 T directed towards the -x-axis. What is the magnitude force acting on the proton?


A) 2.6×10-15 N
B) 0 N
C)8.0×10-15 N
D) 1.3×10-15 N
E) 3.9×10-15 N
   
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#1
Staff Member
Educator
10 years ago
F=q(vxB )

=(1.602*10^-19)[(4.0*10^4) j]x(-0.20 i)

=1.2816*10^-15 k N

its directed along the +z axis
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