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teratoma teratoma
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12 years ago
An elevator undergoes constant upward acceleration, taking it from rest to 12.8 m/s in 4.0 s. An 78 kg man stands on a scale in the elevator

Part A (answered) need part B (below)
What does the scale read during the upward acceleration?
Express your answer to two significant figures and include the appropriate units.
   F =1000   N

Part B (need help)
Nearing the top floor, the elevator slows from 12.8  to rest in the last 22.4  of upward travel. Assuming constant acceleration, what's the scale reading during this period?

Express your answer to two significant figures and include the appropriate units.

F = ?
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Replies
wrote...
12 years ago
First you must find the acceleration of the elevator.
Once you have found this, the force on the scale is equal to ma - mg.
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