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jgrins jgrins
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9 years ago
What is the tension in the rope of the figure? (Figure attached below)
 --

I made the assumption that acceleration is zero.* And then found the y-components of each mass. I also found Tm=Tb (m = man; b = box).

Fym = T - Wm = 0
Fyb = T - Wb = 0

So T = Wm which then I substituted in to T - Wb = 0

 Wm - Wb = 0

I found W of both by mg and then solved, but my answer is incorrect and I'm not sure where to go from here.

*I also tried calculating as if there was acceleration and I was still wrong.
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#1
Educator
9 years ago
Answer is 588 N.
rsb
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#2
9 years ago
Here's a similar question:

What is the tension in the rope of the figure? Assume that m = 64 kg.

Answer provided below (Downwards Arrow)
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jgrins Author
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#3
9 years ago
Thanks, but I'm still kind of confused by the work you show. I know that they're in equilibrium so why do you put your equations  equal to ma and not just zero. And what does it say on the bottom (a = what?)

And why do you come up with T = 64g and not T = 100g? Because the tension forces on both sides should the be same right? So I'm just confused why T1 doesn't equal T2?
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AlexxAlexx
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#4
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9 years ago
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jgrins Author
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#5
9 years ago
Wow thanks! This is a great explanation.
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