What is the identity of the precipitate? What is the molarity of the Na2CO3 solution

hsedward

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2 years ago Edited: 2 years ago, hsedward

What is the identity of the precipitate? What is the molarity of the Na2CO3 solution

20.0 mL of an aqueous Na2CO3 solution is mixed with 50.0 mL of 0.400 M LizCO3.
This mixture is then added to 80.0 mL of 0.250 M FeCl3. 2.334 g of precipitate
results. What is the identity of the precipitate? What is the molarity of the Na2CO3 solution? After the precipitation process is complete, the molarity of the Na+ and Li+
ions are?

Post Merge: 2 years ago

it’s Li2CO3 not LizCO3

Quote from: hsedward (2 years ago)

20.0 mL of an aqueous Na2CO3 solution is mixed with 50.0 mL of 0.400 M LizCO3. This mixture is then added to 80.0 mL of 0.250 M FeCl3. 2.334 g of precipitate results. What is the identity of the precipitate? What is the molarity of the Na2CO3 solution? After the precipitation process is complete, the molarity of the Na+ and Li+ ions are?

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bio_man

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Educator

2 years ago Edited: 2 years ago, bio_man

Mixing Na2CO3 with Li2CO3 doesn't do anything.

3 Na2CO3 + 2 FeCl3 \(\rightarrow\) 6 NaCl + Fe2(CO3)3

3 Li2CO3 + 2 FeCl3 \(\rightarrow\) 6 LiCl + Fe2(CO3)3

The solid that forms is Fe2(CO3)3.

You have to do the same thing I did in the previous example you posted here as well.

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hsedward Author

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2 years ago

I’m not sure how do I get the molarity for Na2CO3? can you show me how to do it? The choices are

0.250 M
0.400 M
0.100 M
None of these answers
0.200 M

on the other part of this question by the way I got 1.333 for Fe3+ and 0.400 M for Co3E2-
and got Na+= 0.0533 and Li+=0.276 but not sure if it’s correct, can you help me check please

Quote from: bio_man (2 years ago)

Mixing Na2CO3 with Li2CO3 doesn't do anything. 3 Na2CO3 + 2 FeCl3 \(\rightarrow\) 6 NaCl + Fe2(CO3)3 3 Li2CO3 + 2 FeCl3 \(\rightarrow\) 6 LiCl + Fe2(CO3)3 The solid that forms is Fe2(CO3)3. You have to do the same thing I did in the previous example you posted here as well.

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bio_man

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Educator

2 years ago

I will look into this later, I'm still thinking about the solution. If anything else comes up, please share it with me here

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hsedward Author

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2 years ago Edited: 2 years ago, hsedward

thank you! sure and it’s due in 3 hrs😭

Post Merge: 2 years ago

Quote from: bio_man (2 years ago)

I will look into this later, I'm still thinking about the solution. If anything else comes up, please share it with me here

I only need this 2 questions, what is the molarity of Na2Co3 ? and the molarity of Fe3+ and CO3 E2-

and here’s the options, i chose c earlier and they said it’s wrong
a) [Fe3+] = 0 M; [CO3 E 2-] = 0.0267 M
b) (Fe3+] = 0.250 M; [CO3 E2-] = 0.400 M
c) None of these answers
d) (Fe3+) = 0.133 M; [CO3 2-] = 0.133 M
e) (Fe3+ = 0.0267 M; (CO3 2-] = 0 M

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bio_man

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Educator

2 years ago Edited: 2 years ago, bio_man

Not good news. After I did my calculation, I got different answers then presented, and I don't want you to select "none of these". I'm getting 0.11 M and 0.16 M.

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hsedward Author

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2 years ago

yeah I chose that letter c at first too coz i got 0.400 for CO which is in the letter b and 1.333 for Fe but it’s in letter d, but they said it’s wrong😭how bout the Na2CO3 molarity?

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