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dataplease dataplease
wrote...
Posts: 88
Rep: 1 0
11 years ago
Please help me understand how to solve this problem
I need to find slope intercept form equation of a line that contains point (5,8) and is parallel to y=7x-6


thanks
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wrote...
11 years ago
y-8 = 7(x-5) = 7x-35
y = 7x - 27
wrote...
11 years ago
solution:
[please dont copy only. try to understand first coz i m not providing solution for copy only but for the help in ur learning. so plz dont copy without understanding]

equation is y=7x+c
so, 8=7.5+c  [since it passes through (5,8)]
=>c=8-35=-27

so, equation is y=7x-27

hope it would be helpful
wrote...
11 years ago
y=mx+b
m=7 parallel to y= 7x-6
y=8 x=5 solve for b
8=7*5+b
b=-27
slope intercept form: y=7x-27
wrote...
11 years ago
So basically to get a parallel line to y= 7x -6, you use the same slope for your new equation.
so your slope = 7.
Then to make sure the line goes through the point (5,8) you make an equations using 5 as x and 8 as y.

the equation: 8 = 7(5) + b
                    y = 7x + b     Leftwards Arrow-showing how I plugged in the numbers.
next you multiply 7 X 5 (35) then plug it in.

                   8 = 35 + b
then you solve for b.
                  8     =    35 + b
                 -35     - 35
                  b = -27
Now you have your equation!
          y = 7x - 27
hope I helped!
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