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Rj55 Rj55
wrote...
Posts: 90
Rep: 1 0
11 years ago
A large randomly mating population of butterflies meets all of the criteria for the Hardy Weinberg model. A gene in this population has 3 alleles at equal frequency. If we sample 100 butterflies, how many should be heterozygous for this gene?

A. 2
B. 11
C. 22
D. 37
E. 67
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wrote...
11 years ago
D
wrote...
11 years ago
What I think is:
if we have 3 alleles which we call the m A, B & C, Then: f(A)=f(B)=f(C)
and as the Hardy Weinberg model says:

A^2+B^2+C^2+2AC+2AB+2BC=1 ---------->A^2+A^2+A^2+2A^2+2A^2+2A^2=1----> 9A^2=1-->
f(A)= 1/3
The population of heterozygous are:
2AC+2AB+2BC = 6A^2 = 6/9 = 2/3
so, 2/3 of butterflies are heterozygous and that mean 2/3 of 100 butterflies are heterozygous which is about 67 of them.
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