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Home Q & A Board Science-Related Homework Help Physics
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tomsawyer tomsawyer
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11 years ago
A man is driving a 1000kg car and attempts a high speed turn on an un banked curve with a radius of 50m at 60m/s.
1) What centripetal force is necessary for his car to successfully make the corner?
b) If the coefficient of friction between the tires and the road is .30, is the attempt successful?

Thank you so much!
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wrote...
#1
11 years ago
1
a)  Fc = m*V²/R = 1000*60²/50 = 72000 N

b)  µ(reqd) = V²/(Rg) = 60²/(50*9.8) = 7.35;  Nowhere near successful.

Note: (a) is dependent on the man's mass being zero.....
wrote...
#2
11 years ago
The outward force is mV^2/R = 1000*60^2/50 = 72,000N
If that force is not provided by the tires on the pavement, he will spinout!
The friction force of the tires on the pavement is m*g*Cf = 1000*9.8*Cf
If Cf = 0.3 NO, not enough
The maximum speed he can negotiate this corner at is
9,800*0.3 = 2940 = mV^2/R => 2940*50/1000 = V^2 => V = 12.1m/s
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