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ilikepie1234 ilikepie1234
wrote...
11 years ago
In a circus act, a 66 kg clown is shot from a cannon with an initial velocity of 16 m/s at some unknown angle above the horizontal. A short time later the clown lands in a net that is 4.2 m vertically above the clown's initial position. Disregard air drag. What is the kinetic energy of the clown as he lands in the net?
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iliya1 Author
wrote...
11 years ago
Since air drag is disregarded, we can use conservation of energy.

Initial kinetic energy of clown = ½*66*16² = 8448 J.
Increase in gravitational potential energy of clown = 66*9.8*4.2 = 2716.56 J, assuming acceleration due to gravity = 9.8 m/s².

By conservation of energy, the increase in potential energy of the clown equals his decrease in kinetic energy.

Hence the kinetic energy of clown as he lands in the net = 8448 - 2716.56 = 5700 J, to 2 significant figures.
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