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Home Q & A Board Science-Related Homework Help Mathematics
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biostudent123 biostudent123
wrote...
Posts: 105
Rep: 1 0
10 years ago
A circle has the equation 3(x-4)^2 + 3y^2 = 12, find the center (h,k) and radius(r)....graph the circle, and find the intercepts (X and y )?

Here is what i found
Radius: 6
Center(h,k): (-4,0)
Graph: I circles 2,4,6 on x axis , with points on 4 and 2
Intercepts: This one is complicated, i get stuck on it help plez

Please let me know if the info above is right.
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wrote...
#1
Staff Member
Educator
10 years ago
Standard equation of a circle with center (h,k) and radius r:

(x - h)2 + (y - k)2 = r2

Let's say you have: 2(x-3)2 + 2y2=8

Therefore:

2(x - 3)2 + 2y2 = 8
(x - 3)2 + y2 = 4
(x - 3)2 + (y - 0)2 = 4
Center is (3,0), radius = 2.
Mastering in Nutritional Biology
Tralalalala Slight Smile
biostudent123 Author
wrote...
#2
10 years ago
Hello, Padre i got the radius, and center right, just dont know how to find intercepts.
wrote...
#3
Staff Member
Educator
10 years ago
(1,0), (5,0)
Mastering in Nutritional Biology
Tralalalala Slight Smile
biostudent123 Author
wrote...
#4
10 years ago
it came out wrong, how did you find that (1,0)(5,0) i got completely different
wrote...
#5
Staff Member
Educator
10 years ago
I figured that the center is at 3,0 and the radius is 2, so I took two to the left and two to the right.
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
#6
10 years ago
To find the intercepts, you sub 0 in for x or y. i.e. If you're finding the y intercept, the x co-ordinate will be 0 so sub 0 in for that etc. Alternatively you can graph it and find them visually similiar to padre's method.
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