This will solve all your problems
https://biology-forums.com/index.php?topic=829.0#topThe last fragment produced in one cycle of the TCA is oxaloacetate. The acetyl CoA is produced by the linker reaction by oxidative decarboxylation of pyruvate. The condensation of the acetyl CoA with OAA via citrate synthase starts the Krebs' TCA cycle . Two moles of pyruvate ( from one mole of glucose ) are converted to two moles of acetyl CoA via the linker reaction then these two moles of acetyl CoA go through the TCA and ultimately there are produced 4 moles of CO2 ( plus the two one gets from the linker reaction ) 6 NADHs (plus the 2 from the linker reaction) , 2 moles of FADH2 and two moles of GTP.
The NADH go through the ETS to produce 3 moles of ATP EACH ( 8 X 3 = 24 ATPs ), the two FADH2s each yield 2 ATPs via the ETS 2 X 2 = 4 ..the two GTPs are each equivalent to an ATP (2 x 1 = 2 ATPs). Plus one gets 2 NADHs from the malate aspartate shuttle that is used to regenerate extramitochondrial NAD+ aerobically..these two NADHs will also yield 2 X 3 = 6 ATPS and one gets 2 ATPs total,from conversion of one mole of glucose to two moles of pyruvate in glycolysis for a grand total for combustion of glucose using glycolysis, the linker reaction ,Krebs' Cycle the M/A shuttle and the ETS of 38 ATPs. There is also produced 6 moles of CO2 via oxidative decarboxylation from the one mole of "BURNED " glucose .