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katybee9 katybee9
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6 years ago
Question text
A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 125 students, 15 cannot taste the PTC. How many students would you expect to be homozygous dominant for the tasting gene? 1 mark

A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 120 students, 3 cannot taste the PTC. Calculate the expected frequencies of the T allele in the student population. 1 mark

Question text
A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 180 students, 34 cannot taste the PTC. Calculate the expected frequencies of the t allele in the student population. 1 mark

Question text
A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 125 students, 6 cannot taste the PTC. How many students would you expect to be heterozygous for the tasting gene?  1 mark

Question text
A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 125 students, 15 cannot taste the PTC. How many students would you expect to be homozygous dominant for the tasting gene? 1 mark

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Educator
6 years ago
A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 125 students, 15 cannot taste the PTC. How many students would you expect to be homozygous dominant for the tasting gene?

\(15 / 125 = 3/25\)

\(\sqrt{\frac{3}{25}}=q=0.3464\)

\(p+q=1\ \rightarrow \ p\ +0.3464=1\)

\(p\ +0.3464=1-0.3464\ =0.6535\)

\(p^{2\ }\rightarrow \left(0.6535\right)^2=0.4271= 42.7 \%\)

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