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fodog414 fodog414
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9 years ago Edited: 9 years ago, fodog414
Using the following data reactions:
delta H° (kJ)
H2(g) + F2(g) Rightwards Arrow 2HF(g)      –542
H2(g) -->2H(g)                        432
F2(g) -->2F(g)                        154
calculate the energy of an H-F bond.
A) 1128 kJ
B) 22 kJ
C) 44 kJ
D) 271 kJ
E) 564 kJ

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Post Merge: 9 years ago

2H= 432/2 to equal 1 H

2F= 154/2 to equal 1 F

2HF= 542/2 to equal 1HF

542/2+154/2+432/2=

564
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