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fjna fjna
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6 years ago

What is the value of the equilibrium constant for the following equilibrium?
   

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wrote...
6 years ago

log10Keq = pKa(acid)  pKa(conjugate acid) = -8  (-1.74) = -6.26

Keq = 10-6.26 = 5.5 x 10-7

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