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fodog414 fodog414
wrote...
Posts: 279
9 years ago
one of the toughest weeks and my "professor" decided not teach the section!!
Instead directing us towards Khan!!!  Frowning Face

I was able to get most of it, but these last few are giving me a hard time

 If $22400 dollars is invested at an interest rate of 6 percent per year, find the value of the investment at the end of 5 years

Daily: 33415.5
compound?

Continuously: I got 33416.87                but they are both wrong
compound?  


second part

Find a possible formula for this function?

x =   0   1   2   3   4
y =   5   35   245   1715   12005

why does 240x-235 not work?


part 3

Your supposed to write (16e^6x)^-1/2 in ae^b form
I got a which is 1/4
but for b why isn't it 3 or 3x?



The last one-  For which values of x is the function f(x) negative?
(inequality form)

-x^2 +10x-24

This one has stumped me the most



Thank you for taking the time in helping me resolve my problems Slight Smile Nerd Face
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4 Replies

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Replies
wrote...
Educator
9 years ago
Hi again, here's a sample question:

If 41200 dollars is invested at an interest rate of 6 percent per year, find the value of the investment at the end of 5 years for the following compounding methods. (a) Annual: Your answer is (b) Semiannual: Your answer is (c) Monthly: Your answer is (d) Daily: Your answer is:

a)
A = 41200 * ( 1 + 0.06)^5 = 55134.89 $

b)
A = 41200 * ( 1 + 0.06/2)^(5*2) = 55369.35 $

c)
A = 41200 * ( 1 + 0.06/12)^(5*12) = 55572.62 $

d)
A = 41200 * ( 1 + 0.06/365)^(5*365) = 55612.81 $

If 42800 dollars is invested at an interest rate of 6 percent per year, find the value of the investment at th?
(a) Annual:
Your answer is
(b) Semiannual:
Your answer is
(c) Monthly:
Your answer is
(d) Daily:
Your answer is
(e) Continuously:
Your answer is:

F = P(1 + 0.06/n)^(nt)

Where....
F is the final amount
P is the beginning amount (42800)
n is the number of compounding periods
t is the number of years (i'm assuming 1 year for these problems)

(a) annual compounding

F = 42800(1+0.06)^1 = 45,368.00

(b) semi-annual compounding

F = 42800(1+0.06/2)^2 = 45,406.52

(c) monthly compounding

F = 42800(1+0.06/12)^12 = 45,439.81

(d) daily compounding

F = 42800(1+0.06/365)^365 = 45,446.38

(e) continuous compounding

For this special case you can use F = 42800e^(0.06)

F = 45,446.60
fodog414 Author
wrote...
9 years ago
Thanks bio man for answering one of my questions Smiling Face with Open Mouth though Continuously compounding was incorrect, are there any similar questions on the other few?
wrote...
Educator
9 years ago
Find a possible formula for this function?

x =   0   1   2   3   4
y =   5   35   245   1715   12005

This part?
fodog414 Author
wrote...
9 years ago
Sure Slight Smile
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