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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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jschroeder96 jschroeder96
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12 years ago
A 325 mL sample of gas is initially at a pressure of 721 torr and a temperature of 32°C. If this gas is compressed to a volume of 286 mL and the pressure increases to 901 torr, what will be the new temperature of the gas
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#1
12 years ago
Using the Combined Gas Law equation, you can solve this equation.

P1V1/T1=P2V2/T2

In this case:
P1 = 721 torr  P2 = 901 torr
V1 = 325 mL   V2 = 286 mL
T1 = 32 C      T2 = ?

First, convert Celsius to Kelvin by adding 273 to the temperature:
32+273= 305K

Therefore:
T2 = P2V2T1/P1V1

721 torr * 325 mL/305K = 901 torr * 286 mL/T2

T2 = 901 torr *286 mL * 305K / 721 torr * 325mL

T2 = 335.41K - 273 = 62.41 Celsius

So,

T2 = 62.41 degrees Celsius
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