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Posts: 25146
A year ago
\(\left[4\sqrt{x}^2-1\right]\cdot 2\sqrt{x}\)

Distribute the 2 to the two terms inside the brackets

\(4\sqrt{x}^2\cdot 2\sqrt{x}-2\sqrt{x}\)

\(8x\sqrt{x}-2\sqrt{x}\)

\(2\sqrt{x}\left(4x-1\right)\)
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