Determine the mass of 1.20 x 10^29 molecules of N2O5.

Jess8219

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3 years ago

Determine the mass of 1.20 x 10^29 molecules of N2O5.

quantities of chemical reactions

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bio_man

wrote...

Educator

3 years ago

Are you sure about this number? 1.20 x 10^29 molecules of N2O5, seems too big... Anyway, recall that 1 mole of N2O5 = 6.02214076×10²³ molecules of N2O5

So:

1.20 x 10^29 molecules of N2O5 X ( 1 mole of N2O5 / 6.02214076×10²³ molecules of N2O5 ) = 199264.7123 moles of N2O5.

Find the molar mass of N2O5; it is 108.01 g/mol

Multiply 108.01 g/mol by 199264.7123 moles of N2O5, you get the mass 2.15 x 10^7 grams.

Let me know if this helps...

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Jess8219 Author

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3 years ago

i'm not getting the same answer for some reason, mind showing how you did using a calculator?

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bio_man

wrote...

Educator

3 years ago

I was thinking something along the lines of this:

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Jess8219 Author

wrote...

3 years ago

not getting 2.15 x 10^7...

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bio_man

wrote...

Educator

3 years ago

Here's what it looks on the calc:

I just wrote it in scientific notation because the number is in the billions!

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Jess8219 Author

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3 years ago

ok got it now, wasn't working the first time

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bio_man

wrote...

Educator

3 years ago

Quote from: Jess8219 (3 years ago)

ok got it now, wasn't working the first time

Working on your other question now.

Curious, do you have the answers to these to double-check ?

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Jess8219 Author

wrote...

3 years ago

unfortunately not, usually I have to figure it out on my own

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bio_man

wrote...

Educator

3 years ago

No worries, just checking

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