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Posts: 33341
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3 years ago
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3 years ago
how is 1 2/3π in the 4th quadrant, I don't understand that.
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3 years ago
1 2/3 is like saying 1 pi plus another 2/3 (two thirds) pi. Assuming you know that 1 pi is half a circle, adding two thirds to that means you've completed almost 2pi (full circle). Therefore, it's safe to say that the angle is in the fourth quadrant.
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wrote...
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3 years ago
Okay I got it, but for the next part (special triangles) does it matter what special triangle you are using, and for the sin ratio I got 1/2 from the special triangle so far, I know you have to use the chart to find the angle but couldn't figure it out, how did u end up getting √3/2? I learned this a while ago, so I sort of forgot how to do this but I'm starting to get it now.
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3 years ago
Look at the angle pi/3 in the special triangle I provided (and that I recommended you memorize). Sine is opposite over hypotenuse, and if you see, opposite is sqrt(3) and hypotenuse is 2.
Mind you, I believe there are 2 special triangles you'll always need to know
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wrote...
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3 years ago
so since since we have pi/3 as our answer to the 4th quadrant, we use that specific special triangle, which also has pi/3 or 60 degrees?
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3 years ago
pi/3 is the reference angle, so you use the special triangle that associates pi/3, pi/6, and pi/2.
Ignore thinking in degrees, as hard as it may be.
I'll be making a video on this tonight; I'll go through all three questions in detail
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wrote...
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3 years ago
okay thank you so much
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wrote...
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3 years ago
Enjoy, and watch carefully!
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wrote...
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3 years ago
thank you so much that really helped me, and I also have one more question, could you also convert the 5pi/3 to degrees to find out which quadrant it is in? Like I did 5pi/3 x 180/pi and got 300 degrees (4th quadrant). That would be another way as well, right?
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3 years ago
It is equivalent to 300 degrees, correct. But it's not an efficient way of doing the problem, because I think you should learn your radians.
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