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Home Q & A Board Science-Related Homework Help Mathematics Calculus
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Acer Matthew Asistio Acer Matthew Asistio
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2 years ago


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Answer rejected by topic starter
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#1
Educator
2 years ago Edited: 2 years ago, bio_man


@@, can you update me on your previous "logic" questions by posting their answers? I'm curious... Slight Smile
Acer M. Author
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#2
2 years ago
We haven't checked it yet. But I'm gonna reply in that post after we checked it. so I can notify you. Thank you so much!
wrote...
#3
2 years ago
This function is do NOT exist at f'(1) because the 2 pieces are not the equal to the same output.

For example:

\(2\sqrt[3]{1}-\left(1\right)^2=1\)

\(\tan \left(1^2-1\right)-5\left(1\right)^{\frac{2}{3}}=-5\)

To be differentiable a function must be continuous. Any function which is differentiable at a point \(x_0\) must also be continuous at \(x_0\). Since the left and right hand limits of \(f\) do not agree, your function is not continuous at 1.
wrote...
#4
Educator
2 years ago
Upwards Arrow Absolutely correct. I made a video:
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