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hsedward hsedward
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3 years ago Edited: 3 years ago, hsedward
20.0 mL of an aqueous Na2CO3 solution is mixed with 50.0 mL of 0.400 M LizCO3.
This mixture is then added to 80.0 mL of 0.250 M FeCl3. 2.334 g of precipitate
results.  What is the identity of the precipitate? What is the molarity of the Na2CO3 solution? After the precipitation process is complete, the molarity of the Na+ and Li+
ions are?
Post Merge: 3 years ago

it’s Li2CO3 not LizCO3
20.0 mL of an aqueous Na2CO3 solution is mixed with 50.0 mL of 0.400 M LizCO3. This mixture is then added to 80.0 mL of 0.250 M FeCl3. 2.334 g of precipitate results. What is the identity of the precipitate? What is the molarity of the Na2CO3 solution? After the precipitation process is complete, the molarity of the Na+ and Li+ ions are?
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wrote...
Educator
3 years ago Edited: 3 years ago, bio_man
Mixing Na2CO3 with Li2CO3 doesn't do anything.

3 Na2CO3 + 2 FeCl3 6 NaCl + Fe2(CO3)3

3 Li2CO3 + 2 FeCl3 6 LiCl + Fe2(CO3)3

The solid that forms is Fe2(CO3)3.

You have to do the same thing I did in the previous example you posted here as well.
hsedward Author
wrote...
3 years ago
I’m not sure how do I get the molarity for Na2CO3? can you show me how to do it? The choices are

0.250 M
0.400 M
0.100 M
None of these answers
0.200 M
 
on the other part of this question by the way I  got 1.333 for Fe3+ and 0.400 M for Co3E2-
 and got Na+= 0.0533 and Li+=0.276 but not sure if it’s correct, can you help me check please
Mixing Na2CO3 with Li2CO3 doesn't do anything. 3 Na2CO3 + 2 FeCl3 6 NaCl + Fe2(CO3)3 3 Li2CO3 + 2 FeCl3 6 LiCl + Fe2(CO3)3 The solid that forms is Fe2(CO3)3. You have to do the same thing I did in the previous example you posted here as well.
wrote...
Educator
3 years ago
I will look into this later, I'm still thinking about the solution. If anything else comes up, please share it with me here
hsedward Author
wrote...
3 years ago Edited: 3 years ago, hsedward
thank you! sure and it’s due in 3 hrs😭
Post Merge: 3 years ago

I will look into this later, I'm still thinking about the solution. If anything else comes up, please share it with me here

I only need this 2 questions, what is the molarity of Na2Co3 ? and the molarity of Fe3+ and CO3 E2-

and here’s the options, i chose c earlier and they said it’s wrong
a) [Fe3+] = 0 M; [CO3 E 2-] = 0.0267 M
b) (Fe3+] = 0.250 M; [CO3 E2-] = 0.400 M
c) None of these answers
d) (Fe3+) = 0.133 M; [CO3 2-] = 0.133 M
e) (Fe3+ = 0.0267 M; (CO3 2-] = 0 M
wrote...
Educator
3 years ago Edited: 3 years ago, bio_man
Not good news. After I did my calculation, I got different answers then presented, and I don't want you to select "none of these". I'm getting 0.11 M and 0.16 M.


hsedward Author
wrote...
3 years ago
yeah I chose that letter c at first too coz i got 0.400 for CO which is in the letter b and 1.333 for Fe but it’s in letter d, but they said it’s wrong😭how bout the Na2CO3 molarity?
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