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darlinlady95 darlinlady95
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2 years ago
A BASE jumper's velocity (in meters per second) after t seconds is given by where m is the mass of the object in kilograms, g = 9.8 m/s2 is the acceleration due to gravity, and k is a physical constant. How fast is the BASE jumper falling at the end of a 12 second delay? Use and Round the answer to one decimal place if necessary.

▸ 58.2 m/s

▸ 698 m/s

▸ 63.2 m/s

▸ 19.2 m/s
Textbook 
Calculus: Early Transcendentals

Calculus: Early Transcendentals


Edition: 3rd
Authors:
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noodlelickernoodlelicker
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2 years ago
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I appreciate what you did here, answered it right Smiling Face with Open Mouth
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