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Sadah_17 Sadah_17
wrote...
Posts: 83
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2 years ago
Did I do it right?



Results: Molarity of NaOH: 0.251 M NaOH Trial 1 Trial 2 Trial 3 9.15ml 9.19ml Volume of NaOH used to reach equivalence point (ml) 9.26 ml Average volume of NaOH used to reach equivalence point (L) 9.20m1/0.00924 Calculations: 1. What is the number of moles of NaOH needed to reach the equivalence point?
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kdot14kdot14
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Posts: 62
2 years ago
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