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Home Q & A Board Biology-Related Homework Help General Biology
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starfall27 starfall27
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12 years ago
18.  You are studying a population of geese in which there are two color phases, brown and gray. Color in this species is controlled by a single gene, with brown dominant to gray. A random sample of 250 geese shows that 210 are brown. What percentage of the brown geese are heterozygous? (Assume that the population is in Hardy-Weinberg equilibrium.)  
A.  36%
B.  43%
C.  48%
D.  57%
E.  84%

This is the answer I came up with but am not sure. When I look it up online it says D is the answer.


Total individual = 250
Brown = 210
Grey = 250 - 210 = 40
q^2(aa) = 40/250 = 0.16
q(a) = SQRT 0.16 = 0.4
p(A) = 1 - 0.4 = 0.6
Percentage of brown heterozygous, 2pq(Aa) = 2 x 0.6 x 0.4 = 0.48 = 48%
The answer: C. 48%
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#1
Educator
12 years ago
Quote from: starfall27 (12 years ago)
C.  48%

That is the answer for sure... The answer you found online saying it's D, is wrong. It is Rightwards Arrow C
Answer accepted by topic starter
starfall27 Authorstarfall27
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#2
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12 years ago
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#3
Educator
12 years ago
Quote from: starfall27 (12 years ago)
Thank you so much!!!  Slight Smile

You're welcome.
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