× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
r
4
New Topic  
Hondo Hondo
wrote...
Posts: 2
Rep: 0 0
A year ago
An object with a mass of 0.75 kg is projected over a horizontal surface with a speed of 2.5 m/s. It then comes to rest after 3.0 s.

(e) What is the coefficient of kinetic friction?
Read 83 times
1 Reply

Related Topics

Replies
wrote...
A year ago
The coefficient of kinetic friction can be calculated using the equation:

μk = (2 * (ΔKE)) / (m * (v2 - v1))

Where ΔKE is the change in kinetic energy, m is the mass of the object, and v2 and v1 are the initial and final velocities of the object.

In this case, ΔKE = 0 (since the object comes to rest), m = 0.75 kg, v2 = 0 m/s, and v1 = 2.5 m/s.

Therefore, μk = (2 * 0) / (0.75 * (0 - 2.5)) = 0.
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1272 People Browsing
 126 Signed Up Today
Related Images
  
 143
  
 72
  
 176
Your Opinion
Which industry do you think artificial intelligence (AI) will impact the most?
Votes: 352