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A researcher wishes to estimate the proportion of adults who have high speed internet access what ...
chrysie1981
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A researcher wishes to estimate the proportion of adults who have high speed internet access what ...
A researcher wishes to estimate the proportion of adults who have high speed internet access what size sample should be obtained if she wishes the estimate to be within 0.05 with 95% confirmed
a) she uses a previous estimate of 0.36?
(b) she does not use any prior estimates?
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Now, with a PRELIMINARY ESTIMATE of .36, p̂ = .36, and q̂ = 1 - p̂ = 1 - .36 = .64
Since this is a 99% CONFIDENCE INTERVAL, then significance level is
0.01/2 or 0,005 so zcritical = 2.575
E (Margin of Error) = .05
Therefore, n = p̂q̂ (zc/e)^2
n = 0.03 x 0.64 x (2.575/0.05)^2 = 0.2304x(51.5)^2 = 0.2304 (2,652.25) = 611.0784 , rounded to 612 adults
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chrysie1981
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Thanks for your help!!
zsc999
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this is exactly what I needed
rene_ram97
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This site is awesome
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