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jwalker824 jwalker824
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3 months ago
The thermal decomposition of acetaldehyde, CH3CHO → CH4 + CO, is a second-order reaction.  The following data were obtained at 518°C.
 
Time, s
Pressure CH3CHO,  mmHg
 
0
364
 
42
330
 
105
290
 
720
132
Calculate the rate constant for the decomposition of acetaldehyde from the above data.


▸ 2.2 × 10–3/s

▸ 0.70 mmHg/s

▸ 2.2 × 10–3/mmHg·s

▸ 6.7 × 10–6/mmHg·s

▸ 5.2 × 10–5/mmHg·s
Textbook 
Chemistry

Chemistry


Edition: 11th
Authors:
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elacevedoelacevedo
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3 months ago
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Anonymous
wrote...
2 months ago
Help! The answer is missing an explanation...
wrote...
2 months ago
I just answered a question like this but with the following values



I found the answer to be \(K_2 = 6.74 \times 10^{-6}\;\mathrm{mmHg}^{-1} s^{-1}\)

Here's my work to help you through it!
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