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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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yandy yandy
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11 months ago
For the reaction SbCl5(g) SbCl3(g) + Cl2(g),
         ΔG°f (SbCl5) = –334.34 kJ/mol
         ΔG°f (SbCl3) = –301.25 kJ/mol
         ΔH°f (SbCl5) = –394.34 kJ/mol
         ΔH°f (SbCl3) = –313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.
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Chemistry

Chemistry


Edition: 11th
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moraamoraa
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yandy Author
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11 months ago
this is exactly what I needed
hannahspillett
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Thanks
DaiwalkerX
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This helped my grade so much Perfect
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