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s.h_math s.h_math
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2 months ago Edited: 2 months ago, s.h_math
I am so clueless on how I can get this? I've tried ever calculation in the other hw and on my last try thankfully I still have the same set hw to do similar qs
Post Merge: 2 months ago

This is what I was doing as per calculations:

83.0 x 1 /64.1 x 3/8  x 257
83 x 1/34.1 x 3/16 x 257

What is the maximum mass of S8 that can be produced by combining 83.0 g of each reactant?
8S02 + 16H2S —4 3S8 + 16H20
Step 1: Convert 83.0 g S02 to moles and determine the number of moles of S8 that can form from the available amount of S02
83.0 g S02
moles of S8 produced from S02
mol S02
mol S8

Step 2: Convert 83.0 g 1--12 S to moles and determine the number of moles of S8 that can form from the available amount of 1-12 S.
83.0 gH2S
moles of S8 produced from 1--12S:
mol H2S
mol S8

Step 3: Identify the limiting reactant.
2
Calculate the mass of S8 produced from the number of moles of S8 produced from the limiting reactant.
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bio_manbio_man
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2 months ago
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s.h_math Author
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2 months ago
THANK YOU BIOMAN
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