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# Maximum Mass Of s8

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2 months ago Edited: 2 months ago, s.h_math
 Maximum Mass Of s8 I am so clueless on how I can get this? I've tried ever calculation in the other hw and on my last try thankfully I still have the same set hw to do similar qsPost Merge: 2 months agoThis is what I was doing as per calculations:83.0 x 1 /64.1 x 3/8  x 25783 x 1/34.1 x 3/16 x 257 What is the maximum mass of S8 that can be produced by combining 83.0 g of each reactant? 8S02 + 16H2S —4 3S8 + 16H20 Step 1: Convert 83.0 g S02 to moles and determine the number of moles of S8 that can form from the available amount of S02 83.0 g S02 moles of S8 produced from S02 mol S02 mol S8 Step 2: Convert 83.0 g 1--12 S to moles and determine the number of moles of S8 that can form from the available amount of 1-12 S. 83.0 gH2S moles of S8 produced from 1--12S: mol H2S mol S8 Step 3: Identify the limiting reactant. 2 Calculate the mass of S8 produced from the number of moles of S8 produced from the limiting reactant. Attached file(s)  Thumbnail(s): You must login or register to gain access to these attachments. Read 70 times 2 Replies
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bio_manbio_man
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2 months ago

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s.h_math Author
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2 months ago
 THANK YOU BIOMAN