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hungry22 hungry22
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3 weeks ago

A viscous fluid is flowing through a small tube at a rate of 2.0 × 10−4 m3/s. If the pressure difference between the ends of the tube is doubled and the radius is also doubled, then what is the new rate of flow of the fluid?



6.4 × 10−3 m3/s



5.6 × 10−3 m3/s



4.4 × 10−3 m3/s



3.7 × 10−3 m3/s



2.6 × 10−3 m3/s

Textbook 
College Physics

College Physics


Edition: 5th
Author:
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xxxmedicalxxxmedical
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