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Eieio Eieio
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2 months ago

Find the force (magnitude and direction) exerted on an electron moving vertically upward at a speed of 2.0 × 107 m/s by a horizontal magnetic field of 0.50 T directed north.



1.6 × 10−12 N west



1.6 × 10−12 N east



1.8 × 10−12 N west



1.8 × 10−12 N east

Textbook 
College Physics

College Physics


Edition: 5th
Author:
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jbeejbee
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2 months ago
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