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fashunluvr24 fashunluvr24
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5 months ago
What is the concentration of Pb2+ ions in a solution prepared by adding 5.00 g of lead(II) iodide to 500. mL of 0.150  M KI?
[ Ksp(PbI2)  =1.4 × 10–8]


2.2 × 10–2 M



1.5 × 10–7 M



6.2 × 10–7 M



9.3 × 10–8 M



1.4 × 10–8 M

Textbook 
Chemistry: Atoms First

Chemistry: Atoms First


Edition: 4th
Author:
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sillysquirrelsillysquirrel
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5 months ago
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