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nzp123 nzp123
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11 years ago
An object is thrown vertically upwards at 19.6 m/s. For its complete trip (up and back down to the starting position), calculate its average velocity.
I have tried this question a few different ways and still can't get the right answer. I get t=4seconds and then d=78.4m and Vavg=19.6m/s When the answer should be Vavg=9.8m/s.
Any help would be so great Thanks!
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wrote...
#1
11 years ago
average velocity= total DISPLACEMENT/total time

average velocity=0
wrote...
#2
11 years ago
vf = vi + at
0 = 19.6 -9.81t
t= 2 sec, this is up, so 2 more for down, making total time 4 sec

d = 1/2 a t^2 , for the trip down
d = 19.6 m for the trip down, so round trip is 39 m

Vavg = total d / total time
         39/4 = 9.81 m/s

i wish teachers would use numbers so as not to have answers that are the same as the numbers you put in, it confuses students
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