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Home Q & A Board Science-Related Homework Help High School Level Science
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smilealways smilealways
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11 years ago
In a sample population of 50 peas the number of  Yellow peas is 48 and the number of green peas is 2. the green is homozygous recessive (yy) for colour. the yellow peas may be heterozygous dominant (Yy) or homozygous dominant (yy).

Using the Hardy-Weinberg Principle,

p+q = 1
P^2 + 2pq + q^2 = 1

where, frequency of Y = p and frequency of y = q.

Calculate:
(i) value of q^2
(ii) value for p
(iii) value for q
(iv) how many peas are YY homozygous dominant
(v)what is the frequency of heterozygous peas
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wrote...
#1
11 years ago
q^2= 1/25 -> q=1/5=0.2 the frequency of y is 20 %

p+q=1 -> p=1-q=0.8  the frequency of Y is 80 %

p^2=0.64  thus number of YY homozygous dominant: 0.64*50=32  ; 32 out of 50 peas are YY

2pq=0,32  thus 32 % heterozygous peas
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